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Példa

$\int\limits_0^1 {1\over\sqrt x} dx=$?

Megoldás. $\int\limits_0^1 {1\over\sqrt x} dx=
\lim\limits_{\epsilon\rightarrow 0} \int\l...
...ow 0} [2\sqrt x]_\epsilon^1=
\lim\limits_{\epsilon\rightarrow 0} 2-2\epsilon=2$.



Róbert Vajda 2003-01-14