Példa

$\int {1\over{x^2-5x+6}} dx=\int {1\over{(x-2)(x-3)}} dx=\int {1\over{x-3}}-{1\o... ...\over{x-2}} dx=\ln\vert x-3\vert-\ln\vert x-2\vert=\ln\vert{x-3\over{x-2}}\vert$